Election in Massachusetts
1840 United States presidential election in Massachusetts
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← 1836 | October 30 - December 2, 1840 | 1844 → |
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Turnout | 66.7%[1] 23.3 pp |
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| | | Nominee | William Henry Harrison | Martin Van Buren | | Party | Whig | Democratic | Home state | Ohio | New York | Running mate | John Tyler | none | Electoral vote | 14 | 0 | Popular vote | 72,852 | 52,355 | Percentage | 57.44% | 41.28% | |
County Results Harrison 40-50% 50-60% 60-70% | Van Buren 40-50% | |
President before election Martin Van Buren Democratic | Elected President William Henry Harrison Whig | |
Elections in Massachusetts |
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Massachusetts portal |
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The 1840 United States presidential election in Massachusetts took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.
Results
See also
References
- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "1840 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved December 23, 2013.
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"s/" = Special election |
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| - See also
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