Election in Alaska
1996 United States presidential election in Alaska
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| | | | Nominee | Bob Dole | Bill Clinton | Ross Perot | Party | Republican | Democratic | Reform | Home state | Kansas | Arkansas | Texas | Running mate | Jack Kemp | Al Gore | Pat Choate | Electoral vote | 3 | 0 | 0 | Popular vote | 122,746 | 80,380 | 26,333 | Percentage | 50.80% | 33.27% | 10.90% | |
Borough results Dole 40–50% 50–60% 60–70% | Clinton 30–40% 40–50% 50–60% | |
President before election Bill Clinton Democratic | Elected President Bill Clinton Democratic | |
Elections in Alaska |
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The 1996 United States presidential election in Alaska took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for president and vice president.
Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.[1] Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.9% of the popular vote.
With 50.8% of the popular vote, Alaska proved to be Dole's fifth strongest state in the 1996 election after Utah, Kansas, Nebraska and Idaho.[2]
Results
Boroughs and Census Areas that flipped from Democratic to Republican
Boroughs that flipped from Independent to Republican
Boroughs and Census Areas that flipped from Republican to Democratic
See also
References
- ^ Dave Leip's Atlas of United States Presidential Election Results - 1996 Alaska Results
- ^ "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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